Gecko [ unitednationsplay.com ]

Linux unitednationsplay.com 3.10.0-1160.45.1.el7.x86_64 #1 SMP Wed Oct 13 17:20:51 UTC 2021 x86_64
nginx/1.20.1
Server IP : 188.130.139.92 & Your IP : 3.15.22.202
Domains : Cant Read [ /etc/named.conf ]
User : web

Name	Size	Permission	Date
LICENSE	1.96 KB	-rw-rw-r--	2022-08-30 11:49
README.md	499 B	-rw-rw-r--	2022-08-30 11:49
abbrev.js	1.72 KB	-rw-rw-r--	2022-08-30 11:49
package.json	509 B	-rw-rw-r--	2022-08-30 11:49

Rename

module.exports = exports = abbrev.abbrev = abbrev

abbrev.monkeyPatch = monkeyPatch

function monkeyPatch () {
  Object.defineProperty(Array.prototype, 'abbrev', {
    value: function () { return abbrev(this) },
    enumerable: false, configurable: true, writable: true
  })

Object.defineProperty(Object.prototype, 'abbrev', {
    value: function () { return abbrev(Object.keys(this)) },
    enumerable: false, configurable: true, writable: true
  })
}

function abbrev (list) {
  if (arguments.length !== 1 || !Array.isArray(list)) {
    list = Array.prototype.slice.call(arguments, 0)
  }
  for (var i = 0, l = list.length, args = [] ; i < l ; i ++) {
    args[i] = typeof list[i] === "string" ? list[i] : String(list[i])
  }

// sort them lexicographically, so that they're next to their nearest kin
  args = args.sort(lexSort)

// walk through each, seeing how much it has in common with the next and previous
  var abbrevs = {}
    , prev = ""
  for (var i = 0, l = args.length ; i < l ; i ++) {
    var current = args[i]
      , next = args[i + 1] || ""
      , nextMatches = true
      , prevMatches = true
    if (current === next) continue
    for (var j = 0, cl = current.length ; j < cl ; j ++) {
      var curChar = current.charAt(j)
      nextMatches = nextMatches && curChar === next.charAt(j)
      prevMatches = prevMatches && curChar === prev.charAt(j)
      if (!nextMatches && !prevMatches) {
        j ++
        break
      }
    }
    prev = current
    if (j === cl) {
      abbrevs[current] = current
      continue
    }
    for (var a = current.substr(0, j) ; j <= cl ; j ++) {
      abbrevs[a] = current
      a += current.charAt(j)
    }
  }
  return abbrevs
}

function lexSort (a, b) {
  return a === b ? 0 : a > b ? 1 : -1
}